x^2+490x-2200=0

Solution for x^2+490x-2200=0 equation:

x^2+490x-2200=0

a = 1; b = 490; c = -2200;
Δ = b2-4ac
Δ = 4902-4·1·(-2200)
Δ = 248900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{248900}=\sqrt{100*2489}=\sqrt{100}*\sqrt{2489}=10\sqrt{2489}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(490)-10\sqrt{2489}}{2*1}=\frac{-490-10\sqrt{2489}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(490)+10\sqrt{2489}}{2*1}=\frac{-490+10\sqrt{2489}}{2}
$